What is the difference between deadlock prevention and deadlock resolution? True or false? Embedded hyperlinks in a thesis or research paper. B. The person who said "acceleration goes out" explicitly had an exterior perspective, the one of the rope holder. Read each statement below carefully and state with reasons and examples, if it is true or false; A particle in one-dimensional motion: (a) with zero speed at an instant may have non-zero acceleration at that instant. Direct link to Nikolay's post Technically they are. You'll get a detailed solution from a subject matter expert that helps you learn core concepts. I don't understand the explanation. Can an object accelerate without changing direction? While \(\vec{v}'\) is a new vector, different from \(\vec{v}\), we have stipulated that the speed of the particle is a constant, so the vector \(\vec{v}'\) has the same magnitude as the vector \(\vec{v}\). Explain. The distinction isn't explicit in our minds and we tend to make mistakes regarding it, so that might be one of the reasons why their opinions on the problem differ. The above equation says that the acceleration. For either position you take, use examples as part of your explanation. The speed of the particle is then the rate of change of s, \(\dfrac{ds}{dt}\) and the direction of the velocity is tangent to the circle. To log in and use all the features of Khan Academy, please enable JavaScript in your browser. In fact, your acceleration has to be exactly leftward, at right angles to your velocity because, if your speed is not changing, but your velocity is continually changing, meaning you have some acceleration \(\vec{a}=\dfrac{d\vec{v}}{dt}\), then for every infinitesimal change in clock reading \(dt\), the change in velocity \(d\vec{v}\) that occurs during that infinitesimal time interval must be perpendicular to the velocity itself. It should be clear that it is impossible to have an acceleration pointing in the direction opposite to the direction where the trajectory bends. True or False: A race car driver steps on the gas, changing his speed from 10 m/s to 30 m/s in 4 seconds. If you are driving counterclockwise (as viewed from above) around a circular track, the direction in which you see the center of the circle is continually changing (and that direction is the direction of the centripetal acceleration).